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| author | Tim Northover <tnorthover@apple.com> | 2016-02-17 23:07:04 +0000 |
|---|---|---|
| committer | Tim Northover <tnorthover@apple.com> | 2016-02-17 23:07:04 +0000 |
| commit | 7687bcee4a5a83fc01141f47cc17a64fbdb96207 (patch) | |
| tree | bdeb29a14966664a8c70e94f1a50dfaecc070668 /llvm/lib/Target/WebAssembly/WebAssemblyTargetMachine.cpp | |
| parent | 053ac453b9f8e6045fd915abde13663636383429 (diff) | |
AArch64: always clear kill flags up to last eliminated copy
After r261154, we were only clearing flags if the known-zero register was
originally live-in to the basic block, but we have to do it even if not when
more than one COPY has been eliminated, otherwise the user of the first COPY
may still have <kill> marked.
E.g.
BB#N:
%X0 = COPY %XZR
STRXui %X0<kill>, <fi#0>
%X0 = COPY %XZR
STRXui %X0<kill>, <fi#1>
We can eliminate both copies, X0 is not live-in, but we must clear the kill on
the first store.
Unfortunately, I've been unable to come up with a non-fragile test for this.
I've only seen it in the wild with regalloc-created spills, and attempts to
reproduce that in a reasonable way run afoul of COPY coalescing. Even volatile
asm clobbers were moved around. Should fix the aarch64 bot though.
llvm-svn: 261175
Diffstat (limited to 'llvm/lib/Target/WebAssembly/WebAssemblyTargetMachine.cpp')
0 files changed, 0 insertions, 0 deletions